In Millikan's experiment,static electric char | vedclass

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Question

(A) The total charge on the oil drop is given by $q = n 	imes e$,where $n$ is the number of electrons and $e$ is the elementary charge of an electron

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The total charge on the oil drop is given by $q = n 	imes e$,where $n$ is the number of electrons and $e$ is the elementary charge of an electron $(1.6022 	imes 10^{-19} \ C)$.Given,total charge $q = 1.282 	imes 10^{-18} \ C$.Therefore,the number of electrons $n = \frac{q}{e}$.$n = \frac{1.282 	imes 10^{-18} \ C}{1.6022 	imes 10^{-19} \ C} = 8.001$.Thus,the number of electrons present on the oil drop is $8$.

In Millikan's experiment,static electric charge on the oil drops has been obtained by shining $X$-rays. If the static electric charge on the oil drop is $-1.282 \times 10^{-18} \ C,$ calculate the number of electrons present on it.

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